![]() ![]() Can you explain this answer? covers all topics & solutions for Physics 2023 Exam.įind important definitions, questions, meanings, examples, exercises and tests below for If for a silicon npn transistor, the base to emitter voltage (VBE) is 0.7Vand the collector to base voltage (VCB) is 0.2V, then the transistor is operating in thea)inverse active modeb)cut-off modec)saturation moded)normal active modeCorrect answer is option 'D'. Information about If for a silicon npn transistor, the base to emitter voltage (VBE) is 0.7Vand the collector to base voltage (VCB) is 0.2V, then the transistor is operating in thea)inverse active modeb)cut-off modec)saturation moded)normal active modeCorrect answer is option 'D'. The Question and answers have been prepared Can you explain this answer? for Physics 2023 is part of Physics preparation. If for a silicon npn transistor, the base to emitter voltage (VBE) is 0.7Vand the collector to base voltage (VCB) is 0.2V, then the transistor is operating in thea)inverse active modeb)cut-off modec)saturation moded)normal active modeCorrect answer is option 'D'. Hence, based on the given voltages, the transistor is operating in the normal active mode. This also aligns with the requirements for the normal active mode. This aligns with the requirements for the normal active mode.Īdditionally, VCB is given as 0.2V, which indicates a reverse-biased collector-base junction. In the given question, VBE is given as 0.7V, which indicates a forward-biased base-emitter junction. This is the typical mode of operation for amplification purposes. When VBE is greater than zero (forward-biased) and VCB is less than zero (reverse-biased), the transistor operates in the normal active mode. This means that the base terminal is at a higher potential than the emitter terminal, while the collector terminal is at a lower potential than the base terminal. In an NPN transistor, the base-emitter junction is forward-biased, and the collector-base junction is reverse-biased. To determine the operating mode of the transistor, we need to analyze the relationship between VBE and VCB. These voltages represent the potential differences between the respective terminals. In the given question, the base to emitter voltage (VBE) is given as 0.7V and the collector to base voltage (VCB) is given as 0.2V. These modes include the inverse active mode, cut-off mode, saturation mode, and normal active mode.īase to Emitter Voltage (VBE) and Collector to Base Voltage (VCB) The operating modes of a silicon NPN transistor are determined by the relationship between the voltages applied to its three terminals: the base (B), emitter (E), and collector (C). Operating Modes of a Silicon NPN Transistor ![]()
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